18x^2+3x-36=0

Solution for 18x^2+3x-36=0 equation:

18x^2+3x-36=0

a = 18; b = 3; c = -36;
Δ = b2-4ac
Δ = 32-4·18·(-36)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-51}{2*18}=\frac{-54}{36}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+51}{2*18}=\frac{48}{36}
=1+1/3
$